2006 ATP Buenos Aires – Doubles

František Čermák and Leoš Friedl were the defending champions.

Doubles
2006 ATP Buenos Aires
Champions František Čermák
Leoš Friedl
Runners-up Vasilis Mazarakis
Boris Pašanski
Final score6–1, 6–2

Čermák and Friedl successfully defended their title, defeating Vasilis Mazarakis and Boris Pašanski 6–1, 6–2 in the final.

Seeds

Draw

Key

Draw

First Round Quarterfinals Semifinals Final
1 F Čermák
L Friedl
6 6  
  D Škoch
J Vaněk
1 2   1 F Čermák
L Friedl
6 5 [11]
  A Montañés
A Portas
3 0     C Berlocq
P Starace
2 7 [9]
  C Berlocq
P Starace
6 6   1 F Čermák
L Friedl
5 6 [11]
3 M García
S Prieto
6 6     A Martín
F Vicente
7 3 [9]
  N Almagro
T Cibulec
3 1   3 M García
S Prieto
5 64  
WC JM del Potro
J Mónaco
3 6 [7]   A Martín
F Vicente
7 77  
  A Martín
F Vicente
6 3 [10] 1 F Čermák
L Friedl
6 6  
WC E Massa
L Mayer
2 6 [5]   V Mazarakis
B Pašanski
1 2  
  O Patience
F Serra
6 2 [10]   O Patience
F Serra
     
  A di Mauro
F Volandri
2 3   4 A Calleri
G Etlis
w/o    
4 A Calleri
G Etlis
6 6   4 A Calleri
G Etlis
     
  M Daniel
F Saretta
62 6 [8]   V Mazarakis
B Pašanski
w/o    
  V Mazarakis
B Pašanski
77 1 [10]   V Mazarakis
B Pašanski
4 6 [12]
  JC Ferrero
S Ventura
6 6     JC Ferrero
S Ventura
6 4 [10]
2 M Fyrstenberg
M Matkowski
4 3  

References

This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.