2019 Thoreau Tennis Open – Doubles

Angela Kulikov and Rianna Valdes won the title, defeating Elizabeth Halbauer and Ingrid Neel in the final, 7–6(7–3), 4–6, [17–15].

Doubles
2019 Thoreau Tennis Open
Champions Angela Kulikov
Rianna Valdes
Runners-up Elizabeth Halbauer
Ingrid Neel
Final score7–6(7–3), 4–6, [17–15]

This was the first edition of the tournament.[1]

Seeds

Draw

Key

Draw

First Round Quarterfinals Semifinals Final
1 D Kovinić
N Stojanović
6 6
  M Mateas
P Udvardy
2 4 1 D Kovinić
N Stojanović
3 3
  E Halbauer
I Neel
6 6 E Halbauer
I Neel
6 6
  K Fahey
M Westby
1 4 E Halbauer
I Neel
77 77
4 O Govortsova
V Savinykh
68 7 [10] 4 O Govortsova
V Savinykh
63 64
  A Bondár
P Ormaechea
710 5 [1] 4 O Govortsova
V Savinykh
5 6 [10]
  Z Hives
B Woolcock
6 2 [5] S Marand
C Whoriskey
7 4 [6]
  S Marand
C Whoriskey
3 6 [10] E Halbauer
I Neel
63 6 [15]
WC B Collens
N Semenovski
2 1 WC A Kulikov
R Valdes
77 4 [17]
  S Xu
X You
6 6 S Xu
X You
1 2
  M Bolkvadze
E Gorgodze
77 5 [4] 3 P-h Chen
Y-c Hsieh
6 6
3 P-h Chen
Y-c Hsieh
64 7 [10] 3 P-h Chen
Y-c Hsieh
2 4
  S Chang
A Mueller
3 2 WC A Kulikov
R Valdes
6 6
WC A Kulikov
R Valdes
6 6 WC A Kulikov
R Valdes
7 4 [10]
WC E Campbell
A Robins
2 0 2 B Schoofs
Y Wickmayer
5 6 [7]
2 B Schoofs
Y Wickmayer
6 6

References

  1. "W60 Concord". www.itftennis.com.
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