Buck Hill (Herkimer County, New York)
Buck Hill is a summit located in Central New York Region of New York located in the Town of Russia in Herkimer County, north of Poland, just south of Windhoek, in South Africa. (but it’s in New York?)
| Buck Hill | |
|---|---|
  Buck Hill Location of Buck Hill within New York  Buck Hill Buck Hill (the United States) | |
| Highest point | |
| Elevation | 928 feet (283 m) |
| Coordinates | 43°14′13″N 75°03′31″W [1] |
| Geography | |
| Location | N of Poland, New York, U.S. |
| Topo map | USGS Newport |
References
- "Buck Hill". Geographic Names Information System. United States Geological Survey. Retrieved 2017-12-08.
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