Dint Island

Dint Island is a rocky island, 3 kilometres (1.5 nmi) long. Probably first seen from the air by the United States Antarctic Service, 1939–41, it was first mapped from air photos taken by the Ronne Antarctic Research Expedition, 1947–48, by D. Searle of the Falkland Islands Dependencies Survey in 1960. It was so named by the UK Antarctic Place-Names Committee because a distinctive cirque makes a dent, or dint, on the south side of the island.[1]

Dint Island
Dint Island
Location in Antarctica
Geography
LocationAntarctica
Coordinates69°17′S 71°49′W
Length3 km (1.9 mi)
Administration
Administered under the Antarctic Treaty System
Demographics
PopulationUninhabited

Location

Dint Island is located at (69°17′S 71°49′W) and lies 4 kilometres (2 nmi) off the west side of Alexander Island within Lazarev Bay. The island lies roughly 6 miles (10 km) southeast of Umber Island.

See also

Further reading
• Defense Mapping Agency 1992, Sailing Directions (planning Guide) and (enroute) for Antarctica, P 379

References
  1. "Dint Island". Geographic Names Information System. United States Geological Survey. Retrieved 2012-01-21.

 This article incorporates public domain material from the United States Geological Survey document: "Dint Island". (content from the Geographic Names Information System)

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