Hockey-stick identity

or equivalently, the mirror-image by the substitution :

Pascal's triangle, rows 0 through 7. The hockey stick identity confirms, for example: for n=6, r=2: 1+3+6+10+15=35.

In combinatorial mathematics, the identity

is known as the hockey-stick[1] or Christmas stocking identity.[2] The name stems from the graphical representation of the identity on Pascal's triangle: when the addends represented in the summation and the sum itself are highlighted, the shape revealed is vaguely reminiscent of those objects.

Proofs

The inductive and algebraic proofs both make use of Pascal's identity:

Inductive proof

This identity can be proven by mathematical induction on .

Base case Let ;

Inductive step Suppose, for some ,

Then

Algebraic proof

We use a telescoping argument to simplify the computation of the sum:

A combinatorial proof

Imagine that we are distributing indistinguishable candies to distinguishable children. By a direct application of the stars and bars method, there are

ways to do this. Alternatively, we can first give candies to the oldest child so that we are essentially giving candies to kids and again, with stars and bars and double counting, we have

which simplifies to the desired result by taking and , and noticing that :

Another combinatorial proof

We can form a committee of size from a group of people in

ways. Now we hand out the numbers to of the people. We can divide this into disjoint cases. In general, in case , , person is on the committee and persons are not on the committee. This can be done in

ways. Now we can sum the values of these disjoint cases, getting

See also

References

  1. CH Jones (1996) Generalized Hockey Stick Identities and N-Dimensional Block Walking. Fibonacci Quarterly 34(3), 280-288.
  2. W., Weisstein, Eric. "Christmas Stocking Theorem". mathworld.wolfram.com. Retrieved 2016-11-01.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.