Iron law of prohibition

A charango used to smuggle cocaine.

Thornton published research showing that the potency of marijuana increased in response to higher enforcement budgets. He later expanded this research in his dissertation to include other illegal drugs and alcohol during Prohibition in the United States (1920–1933). The basic approach is based on the Alchian and Allen Theorem. This argument says that a fixed cost (e.g. transportation fee) added to the price of two varieties of the same product (e.g. high quality red apple and a low quality red apple) results in greater sales of the more expensive variety. When applied to rum-running, drug smuggling, and blockade running the more potent products become the sole focus of the suppliers. Thornton notes that the greatest added cost in illegal sales is the avoidance of detection.[4] Thornton says that if drugs are legalized, then consumers will begin to wean themselves off the higher potency forms, for instance with cocaine users buying coca leaves, and heroin users switching to opium.[5]

The popular shift from beer to wine to hard liquor during the US Prohibition era[6] has a parallel in the narcotics trade in the late 20th century. Bulky opium was illegal, so refined heroin became more prevalent, albeit with significant risk from blood-borne disease because of injection by needle, and far greater risk of death from overdose. Marijuana was also found too bulky and troublesome to smuggle across borders, so smugglers turned to refined cocaine with its much higher potency and profit per pound.[7] Cowan wrote in 1986 that crack cocaine was entirely a product of the prohibition of drugs.[2] Clinical psychiatrist Michael J. Reznicek adds crystal meth to this list.[8] In the 2010s the iron law has been invoked to explain why heroin is displaced by fentanyl and other, even stronger, synthetic opioids.[9]

With underage drinking by teens in the U.S., one of the impacts of laws against possession of alcohol by minors is that teens tend to prefer distilled spirits, because they are easier to conceal than beer.

Consider the situation where there are two substitute goods ${\displaystyle x_{H}}$ and ${\displaystyle x_{L}}$, denoting the higher and lower quality goods with respective prices ${\displaystyle p_{H}}$ and ${\displaystyle p_{L}}$, and where ${\displaystyle p_{H}>p_{L}}$ i.e. the higher quality good has a higher price. Each of these goods has a compensated demand curve (a demand curve which holds utility constant) of the form

$${\displaystyle x_{i}=h_{i}(p_{H},p_{L},U),\quad i\in \{H,L\},}$$

where

$${\displaystyle \left(h_{i}(p_{H},p_{L},U)\right)_{i\in \{H,L\}}=h(p_{H},p_{L},U))={\underset {x\in \mathbb {R} _{+}^{2}:\,u(x)\geq U}{\operatorname {arg\,min} }}\,\sum _{i\in \{H,L\}}p_{i}x_{i},}$$

with ${\displaystyle u(x)}$ denoting the utility function of the consumer. Furthermore, we will also assume that income is held constant, as income effects are indeterminate in forecasting changes in demand.

Suppose that there is an associated cost ${\displaystyle \tau }$ that is added to each good due to transport costs. We want to know how the ratio of demand ${\displaystyle x_{H}/x_{L}}$ changes for the two goods based on ${\displaystyle \tau }$. Taking the derivative with respect to ${\displaystyle \tau }$ yields

$${\displaystyle {\partial \over {\partial \tau }}\left({x_{H} \over {x_{L}}}\right)={1 \over {x_{L}}}{\partial x_{H} \over {\partial \tau }}-{x_{H} \over {x_{L}^{2}}}{\partial x_{L} \over {\partial \tau }}.}$$

(1)

From our assumptions, we have that the total price for each item is ${\displaystyle p_{i}+\tau }$. Therefore, we may compute ${\displaystyle \partial x_{i}/\partial \tau }$ to be

$${\displaystyle {\partial x_{i} \over {\partial \tau }}={\partial x_{i} \over {\partial p_{H}}}+{\partial x_{i} \over {\partial p_{L}}},\quad i\in \{H,L\}.}$$

We may now rewrite (1) as

$${\displaystyle {\partial \over {\partial \tau }}\left({x_{H} \over {x_{L}}}\right)={x_{H} \over {x_{L}}}\left({\frac {1}{x_{H}}}({\frac {\partial x_{H}}{\partial p_{H}}}+{\frac {\partial x_{H}}{\partial p_{L}}})-{\frac {1}{x_{L}}}({\frac {\partial x_{L}}{\partial p_{H}}}+{\frac {\partial x_{L}}{\partial p_{L}}})\right).}$$

(2)

Finally, using the cross-elasticity of demand,

$${\displaystyle \epsilon _{ij}={\partial x_{i}/x_{i} \over {\partial p_{j}/p_{j}}},\quad i,j\in \{H,L\},}$$

we arrive at the following expression of the derivative

$${\displaystyle {\partial \over {\partial \tau }}\left({x_{H} \over {x_{L}}}\right)={x_{H} \over {x_{L}}}\left({\epsilon _{HH} \over {p_{H}}}+{\epsilon _{HL} \over {p_{L}}}-{\epsilon _{LH} \over {p_{H}}}-{\epsilon _{LL} \over {p_{L}}}\right)={x_{H} \over {x_{L}}}\left({1 \over {p_{H}}}(\epsilon _{HH}-\epsilon _{LH})+{1 \over {p_{L}}}(\epsilon _{HL}-\epsilon _{LL})\right).}$$

(3)

Now, we want to show that ${\displaystyle \partial _{\tau }(x_{H}/x_{L})>0}$, but seem to be stuck with elasticities that are indeterminate. However, Hicks' third law of demand[10] gives us ${\displaystyle \epsilon _{HH}=-\epsilon _{HL}}$ and ${\displaystyle \epsilon _{LH}=-\epsilon _{LL}}$. To see why this is, suppose that we take a more general version of the compensated demand function with ${\displaystyle n}$ goods and compensated demand curves ${\displaystyle h_{i}(p_{1},\dots ,p_{n},U)}$, for ${\displaystyle i=1,\dots ,n}$.

For a homogeneous function ${\displaystyle f(z_{1},\dots ,z_{n},V)}$ of degree ${\displaystyle m}$, defined as

$${\displaystyle f(\lambda z_{1},\dots ,\lambda z_{n},V)=\lambda ^{m}f(z_{1},\dots ,z_{n},V),}$$

Euler's homogeneous function theorem states that

$${\displaystyle mf(z_{1},\dots ,z_{n},V)={\partial f \over {\partial z_{1}}}z_{1}+\cdots +{\partial f \over {\partial z_{n}}}z_{n}.}$$

Compensated demand functions are homogeneous of degree 0, since multiplying all prices by a constant ${\displaystyle \lambda >0}$ yields the same solution to the expenditure minimization problem as the original prices. Thus,

$${\displaystyle 0={\partial x_{i} \over {\partial p_{1}}}p_{1}+\cdots +{\partial x_{i} \over {\partial p_{n}}}p_{n},\quad i=1,\dots ,n.}$$

Dividing by the stock ${\displaystyle x_{i}}$ yields

$${\displaystyle 0={\partial x_{i} \over {\partial p_{1}}}{p_{1} \over {x_{i}}}+\cdots +{\partial x_{i} \over {\partial p_{n}}}{p_{n} \over {x_{i}}}=\sum _{j=1}^{n}\epsilon _{ij},\quad i=1,\dots ,n,}$$

which establishes Hicks' third law of demand.

Using Hicks' law, (3) is rewritten as

$${\displaystyle {\partial \over {\partial \tau }}\left({x_{H} \over {x_{L}}}\right)={x_{H} \over {x_{L}}}\left(-{1 \over {p_{H}}}(\epsilon _{HL}+\epsilon _{LH})+{1 \over {p_{L}}}(\epsilon _{HL}+\epsilon _{LH})\right).}$$

(4)

Suppose for the sake of contradiction that ${\displaystyle {\frac {\partial }{\partial \tau }}\left({\frac {x_{H}}{x_{L}}}\right)\leq 0}$. Then,

$${\displaystyle -{1 \over {p_{H}}}(\epsilon _{HL}+\epsilon _{LH})+{1 \over {p_{L}}}(\epsilon _{HL}+\epsilon _{LH})\leq 0.}$$

By initial assumption, our two goods are substitutes. As such, ${\displaystyle \epsilon _{HL}>0}$ and ${\displaystyle \epsilon _{LH}>0}$, implying that

$${\displaystyle -{\frac {1}{p_{H}}}+{\frac {1}{p_{L}}}\leq 0\quad \Longleftrightarrow \quad p_{L}\geq p_{H}.}$$

But, this contradicts the assumption that ${\displaystyle p_{H}>p_{L}}$. Thus, we conclude that ${\displaystyle {\frac {\partial }{\partial \tau }}\left({\frac {x_{H}}{x_{L}}}\right)>0}$. This implies that as the transport costs increase, the higher quality good will become more prevalent than the lower quality good. In the drug-specific context, as costs associated with drug enforcement increase, the more potent drug will become more prevalent in the illegal drug market.