Lake Seymour (Vermont)

Seymour Lake is located in the town of Morgan in Orleans County, Vermont, an area known as the Northeast Kingdom. The lake was named for Israel Seymour, one of the original grantees. Natives called it Namagonic ("salmon trout spearing place").[1] It is one of only two deep, cold, and oligotrophic lakes in the Clyde River system.[2][3]

Seymour Lake
Seymour Lake- Morgan Vermont
Seymour Lake Show map of Vermont Seymour Lake Show map of the United States
Location	Morgan, Orleans County, Vermont
Coordinates	44°53′49″N 071°58′54″W
Lake type	Glacial lake , ice age
Primary inflows	outlet from Mud Pond, Sucker Brook
Primary outflows	Clyde River
Basin countries	United States
Max. length	3 mi (4.8 km)
Max. width	2 mi (3.2 km)
Surface area	1,732 acres (7.01 km2)
Max. depth	169 ft (52 m)
Surface elevation	1,278 ft (390 m)
Settlements	morgan township

The freshwater lake covers 1,732 acres (7.01 km²) and is 3 miles (4.8 km) long and 2 miles (3.2 km) wide; its maximum depth is 167 feet (51 m). It is shaped like a giant number "7".[4] The lake is fed by two primary streams, an outlet from Mud Pond and Sucker Brook. The lake drains into Echo Pond, which empties into the Clyde River, Lake Memphremagog and, eventually, Canada's St. Lawrence River.

A dam is used for hydroelectric power. Construction on the dam was completed in 1928. It has a normal surface area of 2.8 square miles (7.3 km²). It is owned by Citizens Utilities Company.[5]

The dam is made of stone with a concrete core. The foundation is soil. The height is 7 feet (2.1 m) with a length of 68 feet (21 m). Maximum discharge is 85 cubic feet (2.4 m³) per second. Its capacity is 5,200 acre feet (6,400,000 m³). Normal storage is 3,500 acre feet (4,300,000 m³). It drains an area of 20.1875 square miles (52.285 km²).[5]

The dam was rebuilt in 2004.[3]