Super Bloch oscillations

Normal Bloch oscillations and Super Bloch oscillations are closely connected. In general, Bloch oscillations are a consequence of the periodic structure of the lattice potential and the existence of a maximum value of the Bloch wave vector ${\displaystyle k_{max}}$. A constant force ${\displaystyle F_{0}}$ results in the acceleration of the particle until the edge of the first Brillouin zone is reached. The following sudden change in velocity from ${\displaystyle +\hbar k_{max}/m}$ to ${\displaystyle -\hbar k_{max}/m}$ can be interpreted as a Bragg scattering of the particle by the lattice potential. As a result, the velocity of the particle never exceeds ${\displaystyle |\hbar k_{max}/m|}$ but oscillates in a saw-tooth like manner with a corresponding periodic oscillation in position space. Surprisingly, despite of the constant acceleration the particle does not translate, but just moves over very few lattice sites.

Super Bloch oscillations arise when an additional periodic driving force is added to ${\displaystyle F_{0}}$, resulting in:

${\displaystyle F(t)=F_{0}+\Delta F\sin(\omega t+\varphi )}$

The details of the motion depend on the ratio between the driving frequency ${\displaystyle \omega }$ and the Bloch frequency ${\displaystyle \omega _{B}}$. A small detuning ${\displaystyle \omega -\omega _{B}}$ results in a beat between the Bloch cycle and the drive, with a drastic change of the particle motion. On top of the Bloch oscillation, the motion shows a much larger oscillation in position space that extends over hundreds of lattice sites. Those Super Bloch oscillations directly correspond to the motion of normal Bloch oscillations, just rescaled in space and time.

A quantum mechanical description of the rescaling can be found here.[1] An experimental realization is demonstrated in these.[2][3][4] A theoretical analysis of the properties of Super-Bloch Oscillations, including dependence on the phase of the driving field is found here.[5]