The Code of the Mounted

Raoul Marlin kills a fur trapper, and is captured and imprisoned by members of the Royal Canadian Mounted Police. Snaky, a member of his gang, kills the two Mounties guarding him, and helps him escape, but another Mountie, Jim Wilson, tracks him down and recaptures him. However, as they are making their way back to jail, more members of the gang Marlin belongs to, including the gang's leader, Jean, waylay them and free Marlin once again. Wilson and his partner, Rogers, begin tracking the gang down. The trail leads them to a general store which is owned by Duval, who is Jean's second-in-command, as well as being in love with her. Wilson hatches a plan to go undercover and impersonate a notorious thief and murderer, Benet. When he gets to the store, he witnesses Duval kill an Indian, when the Indian refuses to sell his furs for fifty cents each. Jean tells him to get out of there, but Wilson gives her his story of being Benet, and wanting to partner with her and split the black market in the region with her. Wilson's cover is further bolstered when Rogers begins spreading a "rumor" around town that Wilson is Benet. After spreading the rumor, Rogers leaves to go get more Mounties to help break up the gang.

Duval, jealous of the attention Jean is bestowing on Wilson/Benet, as well as being upset over being shut out of their deal, begins to dig into Benet's history. At the newspaper office, he finds out that the real Benet had been hung a short time earlier. He takes the newspaper article to Jean, who is furious, and gathers her gang to go after Wilson. Just as they are about to hunt Wilson down, Rogers and the others Mounties arrive. Most of the gang is arrested, but Jean and Marlin escape. Wilson takes out after the two. As he catches up with them, Marlin gets a bead on him, but is shot and killed by Jean, who has developed feelings for Wilson. In exchange, Wilson lets Jean escape.