Tsankov Island

Tsankov Island (Bulgarian: Цанков остров, romanized: Tsankov ostrov, IPA: [t͡sɐnˈkɔf ˈɔstrof]) is the mostly ice-covered island 625 m long in west-southwest to west-northeast direction and 216 m wide in the Dannebrog Islands group of Wilhelm Archipelago in the Antarctic Peninsula region. Its surface area is 9.48 ha.[1]

Tsankov Island
Tsankov Island
Location of Tsankov Island
Tsankov Island
Tsankov Island (Antarctic Peninsula)
Geography
LocationAntarctica
Coordinates65°03′58″S 64°08′38″W
ArchipelagoWilhelm Archipelago
Area9.48 ha (23.4 acres)
Length625 m (2051 ft)
Width216 m (709 ft)
Administration
Administered under the Antarctic Treaty System
Demographics
Populationuninhabited

The feature is named after the dermatologist Nikolay Tsankov, participant in the 2010/11 and subsequent Bulgarian Antarctic campaigns.[1]

Location

Tsankov Island is located at 65°03′58″S 64°08′38″W, which is 293 m northwest of Stego Island, 175 m east of Bodloperka Island, 1.18 km southeast of Sprey Island and 1.25 km west-southwest of Taralezh Island. British mapping in 2001.

Maps

See also

  • List of Antarctic and subantarctic islands

Notes

  1. Tsankov Island. SCAR Composite Gazetteer of Antarctica

References

This article includes information from the Antarctic Place-names Commission of Bulgaria which is used with permission.


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