1928 Romanian general election
General elections were held in Romania in December 1928.[1] The Chamber of Deputies was elected on 12 December, whilst the Senate was elected in three stages on 15, 17 and 19 December.[1] The result was a victory for the governing National Peasants' Party-led alliance, which won 348 of the 387 seats in the Chamber of Deputies and 105 of the 110 seats in the Senate elected through universal male vote.[2] Of the 348 Chamber seats won by the alliance, the National Peasants' Party won 326, the Social Democratic Party won 9, the German Party won 8, the Hungarian People's Party won 2 and three were won by Jewish candidates.[2] It is generally regarded as the freest election ever held in Romania until the 1990s.[3]
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All 387 seats in the Chamber of Deputies All 110 seats in the Senate | |||||||||||||||||||||||||||||||||||||||||
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Turnout | 77.4% (0.4%) | ||||||||||||||||||||||||||||||||||||||||
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Results
Party | Chamber | Senate | ||||||
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Votes | % | Seats | +/– | Votes | % | Seats | +/– | |
National Peasants' Party-led alliance | 2,208,922 | 79.2 | 348 | +294 | 105 | +88 | ||
National Liberal Party | 185,939 | 6.7 | 13 | –305 | 0 | –92 | ||
Magyar Party | 172,099 | 6.2 | 16 | New | 3 | New | ||
National Party–People's Party | 70,790 | 2.5 | 5 | +5 | 0 | 0 | ||
Peasants' Party–Lupu | 70,506 | 2.5 | 5 | New | 0 | New | ||
Peasant Workers' Bloc | 38,851 | 1.4 | 0 | New | 0 | New | ||
National-Christian Defense League | 32,273 | 1.2 | 0 | New | 0 | New | ||
Other parties | 8,051 | 0.3 | 0 | – | 3 | – | ||
Jewish Party | 0 | – | 2 | New | ||||
Invalid/blank votes | 53,249 | – | – | – | – | – | – | |
Total | 2,840,680 | 100 | 387 | 0 | 110 | –3 | ||
Registered voters/turnout | 3,671,352 | 77.4 | – | – | – | – | ||
Source: Nohlen & Stöver |
References
- Dieter Nohlen & Philip Stöver (2010) Elections in Europe: A data handbook, p1591 ISBN 978-3-8329-5609-7
- Nohlen & Stöver, pp1610-1611
- Romania from Encyclopædia Britannica.
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