1967 CONCACAF Championship qualification

For the 1967 CONCACAF Championship, a total of 10 teams entered the competition.  Honduras, as the hosts, and  Mexico, as the defending champions, qualified automatically, leaving 4 spots open for competition. The 8 teams were divided into 2 groups in which the top 2 in each group advanced to the final tournament.

Group 1

Played in Kingston, Jamaica.

The group was also referred to as the Red Stripe Trophy within Jamaica. The group was sponsored by Desnoes & Geddes, the brewery of Red Stripe beer.[1]

Pos Team Pld W D L GF GA GD Pts
1  Haiti 4 3 1 0 7 3 +4 7
2  Trinidad and Tobago 4 2 1 1 7 7 0 5
3  Jamaica 4 1 2 1 4 4 0 4
4  Cuba 4 0 2 2 5 7 2 2
5  Netherlands Antilles 4 0 2 2 4 6 2 2
Source:
Jamaica 1–1 Netherlands Antilles

Cuba 1–1 Haiti

Trinidad and Tobago 2–1 Netherlands Antilles
Small
Archibald
Perez  (pen)

Jamaica 2–1 Cuba

Haiti 4–2 Trinidad and Tobago

Netherlands Antilles 2–2 Cuba
Dirks
Perez
Hernandez
Mico

Jamaica 1–1 Trinidad and Tobago

Haiti 1–0 Netherlands Antilles

Trinidad and Tobago 2–1 Cuba

Jamaica 0–1 Haiti

Haiti and Trinidad and Tobago qualified for the final tournament.

Group 2

Played in Ciudad de Guatemala, Guatemala.

Pos Team Pld W D L GF GA GD Pts
1  Guatemala 2 2 0 0 6 2 +4 4
2  Nicaragua 2 1 0 1 4 4 0 2
3  Panama 2 0 0 2 2 6 4 0
Source:
Guatemala 3–1 Panama

Guatemala 3–1 Nicaragua

Panama 1–3 Nicaragua

Guatemala and Nicaragua qualified for the final tournament.

References

  1. "Haitian goalkeeper suspended". Kingston Gleaner. 23 January 1967. p. 28.
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