1968 CONCACAF Champions' Cup

The 1968 CONCACAF Champions' Cup was the 4th edition of the annual international club football competition held in the CONCACAF region (North America, Central America and the Caribbean), the CONCACAF Champions' Cup. It determined that year's football club champion in the CONCACAF region.

1968 CONCACAF Champions' Cup
Tournament details
Dates26 May 1968 – 1 December 1968
Teams10
Final positions
Champions Toluca (1st title)

The tournament was played by 10 teams of 10 nations: Netherlands Antilles, Bermuda, El Salvador, United States, Guatemala, Mexico, Honduras, Suriname, Nicaragua, Costa Rica.

It was played from 26 May till 1 December 1968 under the home/away match system. The tournament was split in 3 zones (North American, Central American and Caribbean), each one qualifying the winner to the final tournament, where the winners of the Central and Caribbean zones played a semi-final to decide who was going to play against the Northern champion in the final. The final was scratched and Toluca were declared champions after both semi-finalists, Aurora and Transvaal, were ejected from the competition due to crowd violence.

Club Deportivo Toluca (actually known as Deportivo Toluca FC) from Mexico won the final, and became for the first time in its history CONCACAF champion.[1][2]

Caribbean zone
22 April 1968 1st leg Scherpenheuvel 1–1 Transvaal
2 May 1968 2nd leg Transvaal 3–1 Scherpenheuvel
  • Transvaal won 4–2 on aggregate score.

Northern zone

First round
26 May 1968 1st leg Somerset Trojans 2–1 NY Greek Americans
2 June 1968 2nd leg NY Greek Americans 1–0 Somerset Trojans
Play-off NY Greek Americans 2–1 Somerset Trojans New York, New York
  • NY Greek Americans won 4–3 on aggregate score.

Second round
29 September 1968 1st leg Toluca 4–1 NY Greek Americans Mexico
CST Epaminondas  14'  85' (pen.)
Ruvalcaba  25'
Linares  59'		  33' (pen.) Tonorezos
6 October 1968 2nd leg NY Greek Americans 2–3 Toluca United States
EST Jurisenvik
Kosmidis 		Ruvalcaba
Dosal
Epaminondas
  • Toluca won 7–3 on aggregate score.

Central American Zone

First round
3 April 1968 1st leg Alajuelense 0–2 Aurora Costa Rica
CST
7 April 1968 2nd leg Aurora 0–1 Alajuelense Guatemala
CST
  • Aurora won 2–1 on aggregate score.
21 April 1968 1st leg Alianza 1–2 Olimpia El Salvador
CST
28 April 1968 2nd leg Olimpia 1–0 Alianza Honduras
CST
  • Olimpia won 3–1 on aggregate score.

Second round
3 November 1968 1st leg Olimpia 1–1 Aurora Honduras
CST
10 November 1968 2nd leg Aurora 4–0 Olimpia Guatemala
CST
  • Aurora won 5–1 on aggregate score.

Semifinals
27 November 1968 1st leg Transvaal 1–1 Aurora Paramaribo, Dutch Guiana
AST Swie
1 December 1968 2nd leg Aurora 0–2 Transvaal Paramaribo, Dutch Guiana
AST
  • At the end of the 2nd leg, Transvaal fans invaded the pitch, but after Aurora fans did the same, a mass brawl broke out between the two sets of fans; both teams were ejected from the competition.

Final

As no final was held after Aurora and Transvaal were disqualified from the competition, Mexican side Toluca were declared champions.[1]

Champion
CONCACAF Champions' Cup
1968 Champion

Toluca
First title

References
  1. Copa de Campeones 1968 on the RSSSF
  2. Todos los campeones de Concacaf on Goal.com, 20 Dec 2020
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