2018 BNP Paribas Primrose Bordeaux – Doubles

Doubles
	2018 BNP Paribas Primrose Bordeaux
Champions	Bradley Klahn; Peter Polansky
Runners-up	Guillermo Durán; Máximo González
Final score	6–3, 3–6, [10–7]

Purav Raja and Divij Sharan were the defending champions but only Raja chose to defend his title, partnering Fabrice Martin. Raja lost in the quarterfinals to Guillermo Durán and Máximo González.

Bradley Klahn and Peter Polansky won the title after defeating Durán and González 6–3, 3–6, [10–7] in the final.

Seeds

First Round					Quarterfinals					Semifinals				Final

1	W Koolhof A Sitak	5	1
	R Albot S Kozlov	7	6			R Albot S Kozlov	2	4
	B Klahn P Polansky	6	6			B Klahn P Polansky	6	6
WC	B Bonzi G Jacq	3	4								B Klahn P Polansky	w/o
4	R Lindstedt A Vasilevski	7⁷	6								C Berlocq T Kokkinakis
WC	M Bourgue K de Schepper	6¹	4		4	R Lindstedt A Vasilevski	3	6⁵
	J Eysseric S Stakhovsky	5	4			C Berlocq T Kokkinakis	6	7⁷
	C Berlocq T Kokkinakis	7	6												B Klahn P Polansky	6	3	[10]
	G Andreozzi A Behar	1	2												G Durán M González	3	6	[7]
WC	G Blancaneaux C Lestienne	6	6		WC	G Blancaneaux C Lestienne	4	6	[8]
	R Arneodo H Nys	6	4	[8]	3	J Cerretani N Monroe	6	4	[10]
3	J Cerretani N Monroe	2	6	[10]						3	J Cerretani N Monroe	1	4
	G Durán M González	7⁷	7								G Durán M González	6	6
	G Barrère N Mahut	6³	5			G Durán M González	6	7
	H Podlipnik-Castillo J Withrow	5	0		2	F Martin P Raja	3	5
2	F Martin P Raja	7	6

This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.