2019 San Benedetto Tennis Cup – Doubles

Doubles
	2019 San Benedetto Tennis Cup
Champions	Ivan Sabanov; Matej Sabanov
Runners-up	Sergio Galdós; Juan Pablo Varillas
Final score	6–4, 4–6, [10–5]

Julian Ocleppo and Andrea Vavassori were the defending champions but only Vavassori chose to defend his title, partnering Andrea Pellegrino.[1] Vavassori lost in the semifinals to Ivan and Matej Sabanov.

Sabanov and Sabanov won the title after defeating Sergio Galdós and Juan Pablo Varillas 6–4, 4–6, [10–5] in the final.

Seeds

First Round					Quarterfinals				Semifinals					Final


					1	A Pellegrino A Vavassori	6	6
	DE Galán S Giraldo	w/o				DE Galán S Giraldo	4	2
	MF Descotte T-l Wu								1	A Pellegrino A Vavassori	6	4	[10]
3	E Gómez LD Martínez									I Sabanov M Sabanov	3	6	[12]
	I Sabanov M Sabanov	w/o				I Sabanov M Sabanov	6	6
WC	Riccardo Balzerani Francesco Forti	3	6	[8]		R Cid Subervi J Hernández-Fernández	1	2
	R Cid Subervi J Hernández-Fernández	6	4	[10]											I Sabanov M Sabanov	6	4	[10]
	V Šafránek J Šátral	6	3	[9]										4	S Galdós JP Varillas	4	6	[5]
ITF	Alexander Igoshin R Safiullin	1	6	[4]^r		V Šafránek J Šátral	0	4
ITF	Riccardo Bonadio Jeroen Vanneste	6	3	[7]	4	S Galdós JP Varillas	6	6
4	S Galdós JP Varillas	1	6	[10]					4	S Galdós JP Varillas	4	6	[10]
	A Bega V Durasovic	7	7						2	A Siljeström S Walków	6	1	[6]
	M Guinard A Müller	5	5			A Bega V Durasovic	5	3
WC	A Basso W Trusendi	4	4		2	A Siljeström S Walków	7	6
2	A Siljeström S Walków	6	6

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