2019 St. Petersburg Open – Doubles

Matteo Berrettini and Fabio Fognini were the defending champions,[1] but Fognini chose not to participate this year. Berrettini played alongside Simone Bolelli, but lost in the final to Divij Sharan and Igor Zelenay, 3–6, 6–3, [8–10].

Doubles
2019 St. Petersburg Open
Champions Divij Sharan
Igor Zelenay
Runners-up Matteo Berrettini
Simone Bolelli
Final score6–3, 3–6, [10–8]

Seeds

Draw

Key

Draw

First Round Quarterfinals Semifinals Final
1 N Mektić
F Škugor
6 6
PR R Berankis
J Tipsarević
3 4 1 N Mektić
F Škugor
6 6
N Monroe
A Vasilevski
6 6 N Monroe
A Vasilevski
4 2
WC E Donskoy
K Kravchuk
3 2 1 N Mektić
F Škugor
5 1
4 M Demoliner
M Middelkoop
6 2 [5] D Sharan
I Zelenay
7 6
D Sharan
I Zelenay
3 6 [10] D Sharan
I Zelenay
7 5 [10]
WC E Karlovskiy
A Rublev
77 2 [2] R Carballés Baena
A Molteni
5 7 [5]
R Carballés Baena
A Molteni
65 6 [10] D Sharan
I Zelenay
6 3 [10]
F Nielsen
T Pütz
6 6 M Berrettini
S Bolelli
3 6 [8]
M Fucsovics
S Travaglia
4 4 F Nielsen
T Pütz
4 6 [7]
M Berrettini
S Bolelli
6 6 M Berrettini
S Bolelli
6 4 [10]
3 R Jebavý
P Oswald
2 2 M Berrettini
S Bolelli
7 7
A Bublik
M Kukushkin
64 3 2 S Gillé
J Vliegen
5 5
A Mannarino
H Nys
77 6 A Mannarino
H Nys
4 4
PR J Kovalík
H Podlipnik Castillo
4 4 2 S Gillé
J Vliegen
6 6
2 S Gillé
J Vliegen
6 6

References

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