Humboldt, Illinois

The village was incorporated on April 16, 1878.[3] The village was named after Alexander von Humboldt, a German natural scientist.[4]

Humboldt is located at 39°36′15″N 88°19′11″W (39.604140, -88.319676).[5]

According to the 2010 census, Humboldt has a total area of 0.35 square miles (0.91 km²), all land.[6]

As of the census[8] of 2000, there were 481 people, 183 households, and 133 families residing in the town. The population density was 856.2 people per square mile (331.6/km²). There were 199 housing units at an average density of 354.2 per square mile (137.2/km²). The racial makeup of the town was 98.75% White, 0.21% Native American, 1.04% from other races. Hispanic or Latino of any race were 3.95% of the population.

There were 183 households, out of which 35.0% had children under the age of 18 living with them, 62.8% were married couples living together, 8.7% had a female householder with no husband present, and 26.8% were non-families. 23.5% of all households were made up of individuals, and 12.0% had someone living alone who was 65 years of age or older. The average household size was 2.63 and the average family size was 3.12.

In the town the population was spread out, with 27.4% under the age of 18, 8.5% from 18 to 24, 31.0% from 25 to 44, 21.0% from 45 to 64, and 12.1% who were 65 years of age or older. The median age was 33 years. For every 100 females, there were 90.9 males. For every 100 females age 18 and over, there were 88.6 males.

The median income for a household in the town was $39,375, and the median income for a family was $45,625. Males had a median income of $29,688 versus $20,417 for females. The per capita income for the town was $16,244. About 1.6% of families and 6.7% of the population were below the poverty line, including 5.3% of those under age 18 and 7.5% of those age 65 or over.