McCarthy 91 function

The 91 function was introduced in papers published by Zohar Manna, Amir Pnueli and John McCarthy in 1970. These papers represented early developments towards the application of formal methods to program verification. The 91 function was chosen for being nested-recursive (contrasted with single recursion, such as defining ${\displaystyle f(n)}$ by means of ${\displaystyle f(n-1)}$). The example was popularized by Manna's book, Mathematical Theory of Computation (1974). As the field of Formal Methods advanced, this example appeared repeatedly in the research literature. In particular, it is viewed as a "challenge problem" for automated program verification.

It is easier to reason about tail-recursive control flow, this is an equivalent (extensionally equal) definition:

${\displaystyle M_{t}(n)=M_{t}'(n,1)}$

${\displaystyle M_{t}'(n,c)={\begin{cases}n,&{\mbox{if }}c=0\\M_{t}'(n-10,c-1),&{\mbox{if }}n>100{\mbox{ and }}c\neq 0\\M_{t}'(n+11,c+1),&{\mbox{if }}n\leq 100{\mbox{ and }}c\neq 0\end{cases}}}$

As one of the examples used to demonstrate such reasoning, Manna's book includes a tail-recursive algorithm equivalent to the nested-recursive 91 function. Many of the papers that report an "automated verification" (or termination proof) of the 91 function only handle the tail-recursive version.

This is an equivalent mutually tail-recursive definition:

${\displaystyle M_{mt}(n)=M_{mt}'(n,0)}$

${\displaystyle M_{mt}'(n,c)={\begin{cases}M_{mt}''(n-10,c),&{\mbox{if }}n>100{\mbox{ }}\\M_{mt}'(n+11,c+1),&{\mbox{if }}n\leq 100{\mbox{ }}\end{cases}}}$

${\displaystyle M_{mt}''(n,c)={\begin{cases}n,&{\mbox{if }}c=0{\mbox{ }}\\M_{mt}'(n,c-1),&{\mbox{if }}c\neq 0{\mbox{ }}\end{cases}}}$

A formal derivation of the mutually tail-recursive version from the nested-recursive one was given in a 1980 article by Mitchell Wand, based on the use of continuations.

Example A:

M(99) = M(M(110)) since 99 ≤ 100
      = M(100)    since 110 > 100
      = M(M(111)) since 100 ≤ 100
      = M(101)    since 111 > 100
      = 91        since 101 > 100

Example B:

M(87) = M(M(98))
      = M(M(M(109)))
      = M(M(99))
      = M(M(M(110)))
      = M(M(100))
      = M(M(M(111)))
      = M(M(101))
      = M(91)
      = M(M(102))
      = M(92)
      = M(M(103))
      = M(93)
   .... Pattern continues increasing till M(99), M(100) and M(101), exactly as we saw on the example A)
      = M(101)    since 111 > 100
      = 91        since 101 > 100

Here is an implementation of the nested-recursive algorithm in Lisp:

(defun mc91 (n)
  (cond ((<= n 100) (mc91 (mc91 (+ n 11))))
        (t (- n 10))))

Here is an implementation of the nested-recursive algorithm in Haskell:

mc91 n 
  | n > 100   = n - 10
  | otherwise = mc91 $ mc91 $ n + 11

Here is an implementation of the nested-recursive algorithm in OCaml:

let rec mc91 n =
  if n > 100 then n - 10
  else mc91 (mc91 (n + 11))

Here is an implementation of the tail-recursive algorithm in OCaml:

let mc91 n =
  let rec aux n c =
    if c = 0 then n
    else if n > 100 then aux (n - 10) (c - 1)
    else aux (n + 11) (c + 1)
  in
  aux n 1

Here is an implementation of the nested-recursive algorithm in Python:

def mc91(n: int) -> int:
    """McCarthy 91 function."""
    if n > 100:
        return n - 10
    else:
        return mc91(mc91(n + 11))

Here is an implementation of the nested-recursive algorithm in C:

int mc91(int n)
{
    if (n > 100) {
        return n - 10;
    } else {
        return mc91(mc91(n + 11));
    }
}

Here is an implementation of the tail-recursive algorithm in C:

int mc91(int n)
{
    mc91taux(n, 1);
}

int mc91taux(int n, int c)
{
    if (c != 0) {
        if (n > 100) {
            return mc91taux(n - 10, c - 1);
        } else {
            return mc91taux(n + 11, c + 1);
        }
    } else {
        return n;
    }
}

Here is a proof that

${\displaystyle M(n)={\begin{cases}n-10,&{\mbox{if }}n>100{\mbox{ }}\\91,&{\mbox{if }}n\leq 100{\mbox{ }}\end{cases}}}$

which provides an equivalent non-recursive algorithm to compute ${\displaystyle M}$.

For n > 100, equality follows from the definition of ${\displaystyle M}$. For n ≤ 100, a strong induction downward from 100 can be used.

For 90 ≤ n ≤ 100,

M(n) = M(M(n + 11)), by definition
     = M(n + 11 - 10), since n + 11 > 100
     = M(n + 1)

So M(n) = M(101) = 91 for 90 ≤ n ≤ 100. This can be used as base case.

For the induction step, let n ≤ 89 and assume M(i) = 91 for all n < i ≤ 100, then

M(n) = M(M(n + 11)), by definition
     = M(91), by hypothesis, since n < n + 11 ≤ 100
     = 91, by the base case.

This proves M(n) = 91 for all n ≤ 100, including negative values.

Donald Knuth generalized the 91 function to include additional parameters.[1] John Cowles developed a formal proof that Knuth's generalized function was total, using the ACL2 theorem prover.[2]

• Manna, Zohar; Pnueli, Amir (July 1970). "Formalization of Properties of Functional Programs". Journal of the ACM. 17 (3): 555–569. doi:10.1145/321592.321606.
• Manna, Zohar; McCarthy, John (1970). "Properties of programs and partial function logic". Machine Intelligence. 5. OCLC 35422131.
• Manna, Zohar (1974). Mathematical Theory of Computation (4th ed.). McGraw-Hill. ISBN 9780070399105.
• Wand, Mitchell (January 1980). "Continuation-Based Program Transformation Strategies". Journal of the ACM. 27 (1): 164–180. doi:10.1145/322169.322183.