Rudyard, Montana

Rudyard is located western Hill County at 48°33′38″N 110°33′17″W (48.560633, -110.554737).[2] U.S. Route 2 runs along the southern edge of the community, leading east 41 miles (66 km) to Havre, the county seat, and west 62 miles (100 km) to Shelby.

According to the United States Census Bureau, the CDP has a total area of 0.93 square miles (2.4 km²), all land.[1]

As of the census[5] of 2000, there were 275 people, 126 households, and 71 families residing in the CDP. The population density was 295.8 people per square mile (114.2/km²). There were 155 housing units at an average density of 166.7 per square mile (64.4/km²). The racial makeup of the CDP was 98.18% White, 0.73% Native American, and 1.09% from two or more races. Hispanic or Latino of any race were 0.36% of the population.

There were 126 households, out of which 27.0% had children under the age of 18 living with them, 45.2% were married couples living together, 7.1% had a female householder with no husband present, and 42.9% were non-families. 38.9% of all households were made up of individuals, and 20.6% had someone living alone who was 65 years of age or older. The average household size was 2.18 and the average family size was 2.94.

In the CDP, the population was spread out, with 25.8% under the age of 18, 2.9% from 18 to 24, 25.5% from 25 to 44, 26.2% from 45 to 64, and 19.6% who were 65 years of age or older. The median age was 43 years. For every 100 females, there were 100.7 males. For every 100 females age 18 and over, there were 94.3 males.

The median income for a household in the CDP was $28,393, and the median income for a family was $34,844. Males had a median income of $25,694 versus $15,833 for females. The per capita income for the CDP was $16,889. About 7.2% of families and 9.9% of the population were below the poverty line, including 12.9% of those under the age of 18 and none of those 65 or over.