1904 Major League Baseball season

The 1904 Major League Baseball season was contested from April 14 to October 10, 1904. The Boston Americans and New York Giants finished atop standings for the American League and National League, respectively. There was no postseason, as the Giants declined to meet the Americans in a World Series.

1904 MLB season
LeagueMajor League Baseball
SportBaseball
DurationApril 14 – October 10, 1904
Number of games154
Number of teams16
Pennant Winners
AL championsBoston Americans
  AL runners-upNew York Highlanders
NL championsNew York Giants
  NL runners-upChicago Cubs

Regular-season schedules were increased this season from 140 games to 154 games, with each team now playing the other seven teams in the same league 22 times apiece; this scheduling would be used through the 1918 season.

The St. Louis Browns and Detroit Tigers played 11 consecutive games against each other in September—the first six in Detroit and the final five in St. Louis[1]—the most games played consecutively between two teams in major league history.[2]

Standings

League leaders

 American LeagueNational League
TypeNameStatNameStat
AVGNap Lajoie.376Honus Wagner.349
HRHarry Davis10Harry Lumley9
RBINap Lajoie102Bill Dahlen80
WinsJack Chesbro41Joe McGinnity35
ERAAddie Joss1.59Joe McGinnity1.61

No-hitters

Postseason

No postseason was held this year.

Managers

Events

References

  1. "The 1904 Detroit Tigers Regular Season Game Log". Retrosheet. Retrieved October 9, 2020.
  2. "Games Played by Teams Record Book". Baseball-Almanac.com. Retrieved May 14, 2012.
  3. Pellowski, Michael J (2007). The Little Giant Book of Baseball Facts. United States: Sterling Publishing Co. pp. 352. ISBN 9781402742736.


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