2018 Sopot Open – Doubles

Doubles
	2018 Sopot Open
Champions	Mateusz Kowalczyk; Szymon Walków
Runners-up	Ruben Gonzales; Nathaniel Lammons
Final score	7–6(8–6), 6–3[1]

Mateusz Kowalczyk and Szymon Walków won the title after defeating Ruben Gonzales and Nathaniel Lammons 7–6^(8–6), 6–3 in the final.[1]

This was the first edition of the tournament.[2]

Seeds

First Round					Quarterfinals				Semifinals				Final

1	A Bury A Mies	6	1	[8]
	D Propoggia S Puodziunas	2	6	[10]		D Propoggia S Puodziunas	2	4
WC	K Majchrzak J Zieliński	2	6⁴			M Kowalczyk S Walków	6	6
	M Kowalczyk S Walków	6	7⁷							M Kowalczyk S Walków	7⁷	7
3	F Agamenone V Manafov	6	6⁶	[13]						G Panfil G Sakharov	6²	5
WC	Paweł Ciaś Michał Dembek	3	7⁸	[11]	3	F Agamenone V Manafov	4	4
Alt	J Choinski J Härteis	3	2			G Panfil G Sakharov	6	6
	G Panfil G Sakharov	6	6											M Kowalczyk S Walków	7⁸	6
	A Collarini M Zekić	6	6										2	R Gonzales N Lammons	6⁶	3
	Z Kolář A Motti	4	4			A Collarini M Zekić	2	4
	M Cuevas H Dellien	3	6	[10]		M Cuevas H Dellien	6	6
4	T Bednarek Volodymyr Uzhylovskyi	6	3	[7]						M Cuevas H Dellien
	Vladyslav Orlov A Smirnov	4	6	[6]					2	R Gonzales N Lammons	w/o
WC	K Drzewiecki K Żuk	6	3	[10]	WC	K Drzewiecki K Żuk	3	1
	P Cachín R Olivo	4	2		2	R Gonzales N Lammons	6	6
2	R Gonzales N Lammons	6	6

Szadurski, Szymon (August 5, 2019). "Sopot Open 2018. Włoskie zwycięstwo na kortach w Gdyni". Dziennik Bałtycki (in Polish). Retrieved July 19, 2019.
Ilic, Jovica (May 31, 2018). "Jerzy Janowicz and Tommy Robredo lead inaugural Sopot Open field". worldtennisusa.org. Retrieved July 19, 2019.

This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.