2019 Berkeley Tennis Club Challenge – Doubles

Nicole Gibbs and Asia Muhammad were the defending champions, but both players chose not to participate.[1]

Doubles
2019 Berkeley Tennis Club Challenge
Champions	Madison Brengle Sachia Vickery
Runners-up	Francesca Di Lorenzo Katie Swan
Final score	6–3, 7–5

Madison Brengle and Sachia Vickery won the title, defeating Francesca Di Lorenzo and Katie Swan in the final, 6–3, 7–5.

Seeds

Giuliana Olmos / Luisa Stefani (Semifinals)
Hsieh Yu-chieh / You Xiaodi (Quarterfinals)
Han Na-lae / Hiroko Kuwata (Quarterfinals)
Chen Pei-hsuan / Wu Fang-hsien (Quarterfinals)

Draw

Key

Draw

	First Round							Quarterfinals							Semifinals							Final

	1	G Olmos L Stefani	6	6
		L Cabrera Z Hives	3	4				1	G Olmos L Stefani	6	6
		J Namigata M Yonehara	6	6					J Namigata M Yonehara	1	1
	Alt	F Al-Nabhani D-b Kim	3	3											1	G Olmos L Stefani	3	7⁷	[9]
	3	N-l Han H Kuwata	6	6												F Di Lorenzo K Swan	6	6²	[11]
		H Arakawa A Shimizu	4	4				3	N-l Han H Kuwata	6⁵	3
		F Di Lorenzo K Swan	6	6					F Di Lorenzo K Swan	7⁷	6
		B Boren G Brodsky	3	4																			F Di Lorenzo K Swan	3	5
		K Ahn C Harrison	7⁷	6																			M Brengle S Vickery	6	7
		D Khazaniuk C Simmonds	6⁴	4					K Ahn C Harrison	7⁷	6
	WC	M Thiel C Van Nguyen	2	4				4	P-h Chen F-h Wu	6³	0
	4	P-h Chen F-h Wu	6	6												K Ahn C Harrison	1	0
		M Brengle S Vickery	6⁵	6	[10]											M Brengle S Vickery	6	6
	WC	A Zamarripa M Zamarripa	7⁷	2	[5]				M Brengle S Vickery	6	7
		S Marand T Moore	4	1				2	Y-c Hsieh X You	0	5
	2	Y-c Hsieh X You	6	6

References

Main Draw

"W60 Berkeley". www.itftennis.com.

This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.