2020 Bendigo Challenger – Doubles

Doubles
	2020 Bendigo Challenger
Champions	Nikola Čačić; Denys Molchanov
Runners-up	Marcelo Arévalo; Jonny O'Mara
Final score	7–6(7–3), 6–4

Nikola Čačić and Denys Molchanov won the title after defeating Marcelo Arévalo and Jonny O'Mara 7–6^(7–3), 6–4 in the final.

This was the first edition of the tournament.[1]

Seeds

First Round					Quarterfinals					Semifinals					Final

1	A Molteni H Nys	4	7⁷	[10]
	N Monroe J Withrow	6	6¹	[6]	1	A Molteni H Nys	6	3	[13]
	A Behar M Reid	6	6			A Behar M Reid	1	6	[15]
WC	Jayden Court Alexander Crnokrak	1	3								A Behar M Reid	6	3	[1]
Alt	Sho Shimabukuro M-k Song	6	6								N Čačić D Molchanov	3	6	[10]
	T Matsui Y Nishioka	3	3		Alt	S Shimabukuro M-k Song	4	6³
	B Klein S Puodziunas	6⁴	4			N Čačić D Molchanov	6	7⁷
	N Čačić D Molchanov	7⁷	6													N Čačić D Molchanov	7⁷	6
	S Mukund F Sun	6	6												2	M Arévalo J O'Mara	6³	4
	L Margaroli A Vavassori	3	4			S Mukund F Sun
	G Granollers D Vega Hernández	5	0		3	S Arends C-p Hsieh	w/o
3	S Arends C-p Hsieh	7	6							3	S Arends C-p Hsieh	3	2
WC	C Puttergill D Sweeny	2	4							2	M Arévalo J O'Mara	6	6
WC	M Banes B Ellis	6	6		WC	M Banes B Ellis	7⁷	4	[9]
	A Göransson S Verbeek	6	5	[2]	2	M Arévalo J O'Mara	6⁴	6	[11]
2	M Arévalo J O'Mara	2	7	[10]

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