First Battle of Oituz

First Battle of Oituz
	Part of World War I
Date	12–27 October 1916
Location	Border of Hungary and Romania (today in Bacău and Covasna counties, eastern Romania)
Result	Romanian victory
Belligerents
Romania	Austria-Hungary; Germany
Commanders and leaders
Eremia Grigorescu; Nicolae Sinescu	Charles I; Erich von Falkenhayn

The First Battle of Oituz was fought between 12 and 27 October 1916 between the Kingdom of Romania, Austria-Hungary and the German Empire. It was part of the Romanian operations for the defense of the passes in the Carpathians. The objectives of the operation were to resist the enemy attack on the Transylvanian front, to obtain and maintain a defensive device in the Carpathian alignment and to create the conditions for an eventual counter-offensive. At the end, the Central Powers (Germany and Austria-Hungary) failed to defeat the Romanian forces and the battle was a victory for the latter.[1]

The Austro-Hungarian forces were commanded by Charles I of Austria, heir to the Austro-Hungarian throne, while the German army was commanded by General Erich von Falkenhayn.[2] On the other hand, the Romanian commanders were Eremia Grigorescu and Nicolae Sinescu.[1]

References

Romanian Commission of Military History (1989). Istoria militară a poporului român (in Romanian). 4. Bucharest: Editura Militară.
von Falkenhayn, Erich; Budiș, Alexandru; Franc, C. (1937). Campania Armatei a 9-a împotriva românilor și a rușilor 1916/17 (in Romanian). Verlag nicht ermittelbar. pp. 1–219.

This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.

[:0-1] Romanian Commission of Military History (1989). Istoria militară a poporului român (in Romanian). 4. Bucharest: Editura Militară.

[2] von Falkenhayn, Erich; Budiș, Alexandru; Franc, C. (1937). Campania Armatei a 9-a împotriva românilor și a rușilor 1916/17 (in Romanian). Verlag nicht ermittelbar. pp. 1–219.