Johnson Island (Antarctica)
Johnson Island is an ice-covered island, about 17 kilometres (9 nmi) long and 9 kilometres (5 nmi) wide, lying within the Abbot Ice Shelf, Antarctica, about 26 kilometres (14 nmi) southeast of Dustin Island. The feature was observed and roughly positioned as an "ice rise" by parties from the USS Glacier (AGB-4) in February 1961. It was remapped by the United States Geological Survey from U.S. Navy air photos, 1966, and was named by the Advisory Committee on Antarctic Names for Theodore L. Johnson, an electrical engineer at Byrd Station in 1964–65.[1]
  Johnson Island Location in Antarctica | |
| Geography | |
|---|---|
| Location | Antarctica |
| Coordinates | 72°52′S 93°54′W |
| Administration | |
| Administered under the Antarctic Treaty System | |
| Demographics | |
| Population | Uninhabited |
See also
- List of Antarctic and sub-Antarctic islands
References
- "Johnson Island". Geographic Names Information System. United States Geological Survey. Retrieved 2012-07-27.
This article incorporates public domain material from the United States Geological Survey document: "Johnson Island". (content from the Geographic Names Information System)
| General |
| .svg.png.webp) |
|---|---|---|
| Regions | ||
| Waterways | ||
| Famous explorers | ||
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.