Relativistic quantum chemistry

Beginning in 1935, Bertha Swirles described a relativistic treatment of a many-electron system,[5] in spite of Paul Dirac's 1929 assertion that the only imperfections remaining in quantum mechanics "give rise to difficulties only when high-speed particles are involved, and are therefore of no importance in the consideration of atomic and molecular structure and ordinary chemical reactions in which it is, indeed, usually sufficiently accurate if one neglects relativity variation of mass and velocity and assumes only Coulomb forces between the various electrons and atomic nuclei".[6]

Theoretical chemists by and large agreed with Dirac's sentiment until the 1970s, when relativistic effects were observed in heavy elements.[7] The Schrödinger equation had been developed without considering relativity in Schrödinger's 1926 article.[8] Relativistic corrections were made to the Schrödinger equation (see Klein–Gordon equation) to describe the fine structure of atomic spectra, but this development and others did not immediately trickle into the chemical community. Since atomic spectral lines were largely in the realm of physics and not in that of chemistry, most chemists were unfamiliar with relativistic quantum mechanics, and their attention was on lighter elements typical for the organic chemistry focus of the time.[9]

Dirac's opinion on the role relativistic quantum mechanics would play for chemical systems is wrong for two reasons. First, electrons in s and p atomic orbitals travel at a significant fraction of the speed of light. Second, relativistic effects cause indirect consequences that are especially evident for d and f atomic orbitals.[7]

Relativistic γ as a function of velocity. For a small velocity, the ${\displaystyle E_{\text{rel}}}$ (ordinate) is equal to ${\displaystyle E_{0}=mc^{2},}$ but as ${\displaystyle v_{\text{e}}\to c}$, the ${\displaystyle E_{\text{rel}}}$ goes to infinity.

One of the most important and familiar results of relativity is that the "relativistic mass" of the electron increases as

${\displaystyle m_{\text{rel}}={\frac {m_{\text{e}}}{\sqrt {1-(v_{\text{e}}/c)^{2}}}},}$

where ${\displaystyle m_{e},v_{e},c}$ are the electron rest mass, velocity of the electron, and speed of light respectively. The figure at the right illustrates this relativistic effect as a function of velocity.

This has an immediate implication on the Bohr radius (${\displaystyle a_{0}}$), which is given by

${\displaystyle a_{0}={\frac {\hbar }{m_{\text{e}}c\alpha }},}$

where ${\displaystyle \hbar }$ is the reduced Planck's constant, and α is the fine-structure constant (a relativistic correction for the Bohr model).

Arnold Sommerfeld calculated that, for a 1s orbital electron of a hydrogen atom with an orbiting radius of 0.0529 nm, α ≈ 1/137. That is to say, the fine-structure constant shows the electron traveling at nearly 1/137 the speed of light.[10] One can extend this to a larger element with an atomic number Z by using the expression v ≈ Zc/137 for a 1s electron, where v is its radial velocity. For gold with Z = 79, v ≈ 0.58 c, so the 1s electron will be going 58% of the speed of light. Plugging this in for v/c in the equation for the "relativistic mass", one finds that m_rel = 1.22m_e, and in turn putting this in for the Bohr radius above one finds that the radius shrinks by 22%.

If one substitutes the "relativistic mass" into the equation for the Bohr radius it can be written

${\displaystyle a_{\text{rel}}={\frac {\hbar {\sqrt {1-(v_{\text{e}}/c)^{2}}}}{m_{\text{e}}c\alpha }}.}$

Ratio of relativistic and nonrelativistic Bohr radii, as a function of electron velocity

It follows that

${\displaystyle {\frac {a_{\text{rel}}}{a_{0}}}={\sqrt {1-(v_{\text{e}}/c)^{2}}}.}$

At right, the above ratio of the relativistic and nonrelativistic Bohr radii has been plotted as a function of the electron velocity. Notice how the relativistic model shows the radius decreases with increasing velocity.

When the Bohr treatment is extended to hydrogenic atoms, the Bohr radius becomes

${\displaystyle r={\frac {n^{2}}{Z}}a_{0}={\frac {n^{2}\hbar ^{2}4\pi \varepsilon _{0}}{m_{\text{e}}Ze^{2}}},}$

where ${\displaystyle n}$ is the principal quantum number, and Z is an integer for the atomic number. In the Bohr model, the angular momentum is given as ${\displaystyle mv_{\text{e}}r=n\hbar }$. Substituting into the equation above and solving for ${\displaystyle v_{\text{e}}}$ gives

${\displaystyle r={\frac {n^{2}a_{0}}{Z}}={\frac {n\hbar }{mv_{\text{e}}}},}$

${\displaystyle v_{\text{e}}={\frac {Z}{n^{2}a_{0}}}{\frac {n\hbar }{m}},}$

${\displaystyle {\frac {v_{\text{e}}}{c}}={\frac {Z\alpha }{n}}={\frac {Ze^{2}}{4\pi \varepsilon _{0}\hbar cn}}.}$

From this point, atomic units can be used to simplify the expression into

${\displaystyle v_{\text{e}}={\frac {Z}{n}}.}$

Substituting this into the expression for the Bohr ratio mentioned above gives

${\displaystyle {\frac {a_{\text{rel}}}{a_{0}}}={\sqrt {1-\left({\frac {Z}{nc}}\right)^{2}}}.}$

At this point one can see that a low value of ${\displaystyle n}$ and a high value of ${\displaystyle Z}$ results in ${\displaystyle {\frac {a_{\text{rel}}}{a_{0}}}<1}$. This fits with intuition: electrons with lower principal quantum numbers will have a higher probability density of being nearer to the nucleus. A nucleus with a large charge will cause an electron to have a high velocity. A higher electron velocity means an increased electron relativistic mass, and as a result the electrons will be near the nucleus more of the time and thereby contract the radius for small principal quantum numbers.[11]

The periodic table was constructed by scientists who noticed periodic trends in known elements of the time. Indeed, the patterns found in it is what gives the periodic table its power. Many of the chemical and physical differences between the 6th period (Cs–Rn) and the 5th period (Rb–Xe) arise from the larger relativistic effects for the former. These relativistic effects are particularly large for gold and its neighbors – platinum and mercury. An important quantum relativistic effect is the Van der Waals force.

Color of gold and caesium

Spectral reflectance curves for aluminum (Al), silver (Ag), and gold (Au) metal mirrors

Alkali-metal coloration: rubidium (silvery) versus caesium (golden)

The reflectivity of aluminium (Al), silver (Ag), and gold (Au) is shown in the graph to the right. The human eye sees electromagnetic radiation with a wavelength near 600 nm as yellow. Gold appears yellow because it absorbs blue light more than it absorbs other visible wavelengths of light; the reflected light reaching the eye is therefore lacking in blue compared to the incident light. Since yellow is complementary to blue, this makes a piece of gold under white light appear yellow to human eyes.

The electronic transition from the 5d orbital to the 6s orbital is responsible for this absorption. An analogous transition occurs in silver, but the relativistic effects are smaller than in gold. While silver's 4d orbital experiences some relativistic expansion and the 5s orbital some contraction, the 4d–5s distance in silver is much greater than the 5d–6s distance in gold. The relativistic effects increase the 5d orbital's distance from the atom's nucleus and decrease the 6s orbital's distance.[12]

Caesium, the heaviest of the alkali metals that can be collected in quantities sufficient for viewing, has a golden hue, whereas the other alkali metals are silver-white. However, relativistic effects are not very significant at Z = 55 for caesium (not far from Z = 47 for silver). The golden color of caesium comes from the decreasing frequency of light required to excite electrons of the alkali metals as the group is descended. For lithium through rubidium, this frequency is in the ultraviolet, but for caesium it reaches the blue-violet end of the visible spectrum; in other words, the plasmonic frequency of the alkali metals becomes lower from lithium to caesium. Thus caesium transmits and partially absorbs violet light preferentially, while other colors (having lower frequency) are reflected; hence it appears yellowish.[13]

• Ionization energy
• Electronegativity
• Electron affinity
• Quantum mechanics

• P. A. Christiansen; W. C. Ermler; K. S. Pitzer. Relativistic Effects in Chemical Systems. Annual Review of Physical Chemistry 1985, 36, 407–432. doi:10.1146/annurev.pc.36.100185.002203