Lake Santee, Indiana

Lake Santee is an unincorporated town and census-designated place in Decatur and Franklin counties, Indiana, United States. As of the 2010 census, it had a population of 820.[1]

Lake Santee, Indiana
Location of Lake Santee in Decatur County and Franklin County, Indiana.
Lake Santee
Location of Lake Santee in Decatur County and Franklin County, Indiana.
Coordinates: 39°24′36″N 85°18′27″W
CountryUnited States
StateIndiana
CountyDecatur, Franklin
TownshipFugit, Salt Creek
Area
  Total2.8 sq mi (7.3 km2)
  Land2.5 sq mi (6.4 km2)
  Water0.3 sq mi (0.9 km2)
Elevation
1,015 ft (309 m)
Population
 (2010)[1]
  Total820
ZIP code
47240
FIPS code18-41444[2]

History

Lake Santee was built up in the 1960s as a housing development centered on a reservoir of the same name.[3]

Geography

Lake Santee is located at 39°24′36″N 85°18′27″W in southeastern Indiana. It is situated 13 miles (21 km) northeast of Greensburg and 12 miles (19 km) northwest of Batesville.

According to the U.S. Census Bureau, the CDP has a total area of 2.8 square miles (7.3 km2), of which 2.5 square miles (6.4 km2) is land and 0.35 square miles (0.9 km2), or 12.60%, is water. The water area consists entirely of Lake Santee, the reservoir.[4]

Demographics

Historical population
CensusPop.
U.S. Decennial Census[5]

References


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