Sherman Township, Hardin County, Iowa

Sherman Township is a township located in Hardin County, Iowa. As of the 2010 Census, its population was 738.[4][1]

Sherman Township
Coordinates: 42°20′23″N 093°24′17″W
Country United States
State Iowa
CountyHardin
Area
  Total35.98 sq mi (93.19 km2)
  Land35.98 sq mi (93.19 km2)
  Water(0%) 0 sq mi ((0%) 0 km2)
Elevation1,142 ft (348 m)
Population
 (2000)
  Total461
  Density13.2/sq mi (5.1/km2)
FIPS code468 697[2][3]
GNIS feature ID0468696

History

Sherman Township was founded in 1870.[5] It is named for William Tecumseh Sherman.[6]

References

  1. "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
  2. "U.S. Census website". United States Census Bureau. Retrieved 2008-01-31.
  3. U.S. Geological Survey Geographic Names Information System: Sherman Township, Hardin County, Iowa
  4. "Find a County". National Association of Counties. Retrieved 2011-06-07.
  5. Moir, William J. (1911). Past and Present of Hardin County, Iowa. Unigraphic. pp. 319.
  6. History of Hardin County, Iowa. Union Publishing Company. 1883. pp. 904.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.