Meadow Acres, Wyoming

Meadow Acres is located at 42°51′38″N 106°5′23″W (42.860580, -106.089853).[4]

According to the United States Census Bureau, the CDP has a total area of 1.5 square miles (3.8 km²), of which 1.4 square miles (3.7 km²) is land and 0.1 square mile (0.2 km²) (4.05%) is water.[5]

As of the census[2] of 2000, there were 181 people, 69 households, and 58 families residing in the CDP. The population density was 127.5 people per square mile (49.2/km²). There were 70 housing units at an average density of 49.3/sq mi (19.0/km²). The racial makeup of the CDP was 95.03% White, 0.55% Native American, 1.10% from other races, and 3.31% from two or more races. Hispanic or Latino of any race were 1.66% of the population.

There were 69 households, out of which 30.4% had children under the age of 18 living with them, 73.9% were married couples living together, 7.2% had a female householder with no husband present, and 15.9% were non-families. 13.0% of all households were made up of individuals, and 5.8% had someone living alone who was 65 years of age or older. The average household size was 2.62 and the average family size was 2.83.

In the CDP, the population was spread out, with 22.1% under the age of 18, 6.6% from 18 to 24, 27.6% from 25 to 44, 34.3% from 45 to 64, and 9.4% who were 65 years of age or older. The median age was 43 years. For every 100 females, there were 92.6 males. For every 100 females age 18 and over, there were 88.0 males.

The median income for a household in the CDP was $56,736, and the median income for a family was $56,736. Males had a median income of $43,750 versus $26,406 for females. The per capita income for the CDP was $23,023. None of the population or families were below the poverty line.