1861 United States Senate election in New York

The 1861 United States Senate election in New York was held on February 5, 1861, by the New York State Legislature to elect a U.S. Senator (Class 3) to represent the State of New York in the United States Senate.

1861 United States Senate election in New York
February 5, 1861

Majority vote of each house needed to win
 
Nominee Ira Harris Horatio Seymour
Party Republican Democratic
Senate 22 9
Percentage 68.75% 28.13%
House 88 31
Percentage 68.75% 24.22%

Senator before election

William Seward
Republican

Elected Senator

Ira Harris
Republican

Background

Whig William H. Seward had been re-elected in February 1855 to this seat, had become a Republican upon the foundation of that party in September 1855, and his term would expire on March 3, 1861. Seward did not seek re-election, instead being certain to be appointed to an office in the incoming Abraham Lincoln administration.

At the State election in November 1859, 23 Republicans and 9 Democrats were elected for a two-year term (1860-1861) in the State Senate. At the State election in November 1860, 93 Republicans and 35 Democrats were elected to the Assembly for the session of 1861. The 84th New York State Legislature met from January 1 to April 16, 1861, at Albany, New York.

Candidates

Ira Harris was the candidate of the Republican Party. Harris had been a Whig assemblyman in 1845 and 1846, and a justice of the New York Supreme Court from 1847 to 1859.

Ex-Governor Horatio Seymour (in office 1853-1854) was the candidate of the Democratic Party.

Election

Both in the Assembly and the Senate a strict party vote confirmed the caucus selections.

In the Assembly 119 votes were given. Republicans Smith Anthony (Cayuga Co.), Martin Finch (Essex Co.), Henry A. Prendergast (Chautauqua Co.), Victor M. Rice (Erie Co.) and Perez H. Field (Ontario Co.); and Democrats Luke F. Cozans (NYC), Benjamin H. Long (Erie Co.), N. Holmes Odell (Westchester Co.) and Christian B. Woodruff (NYC); did not vote.

In the State Senate, 31 votes were given. William H. Ferry (Rep., 19th D.) was absent.

Result

Ira Harris was the choice of both the Assembly and the Senate, and was declared elected.

1861 United States Senator election result
Office House Republican Democrat
U.S. Senator State Senate (32 members) Ira Harris 22 Horatio Seymour 9
State Assembly (128 members) Ira Harris 88 Horatio Seymour 31

Aftermath

Harris served one term, and remained in office until March 3, 1867.

Sources

See also

  • United States Senate elections, 1860 and 1861
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.