1868 United States presidential election in New York

1868 United States presidential election in New York
	November 3, 1868
	November 3, 1868
Turnout	91.7%[1] 2.4 pp
President before election; Andrew Johnson; Democratic	Elected President ; Ulysses S. Grant; Republican

The 1868 United States presidential election in New York took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose 33 representatives, or electors to the Electoral College, who voted for president and vice president.

New York voted for the Democratic nominee, former Governor of New York Horatio Seymour, over the Republican nominee, General Ulysses S. Grant. Seymour won his home state by a very narrow margin of 1.18%, making him the first Democratic candidate since Franklin Pierce in 1852 to win the state. Seymour also became the first losing Democratic presidential candidate to win New York.

Results

1868 United States presidential election in New York[2]
Party		Candidate	Running mate	Popular vote		Electoral vote
Party		Candidate	Running mate	Count	%	Count	%
	Democratic	Horatio Seymour of New York	Francis Preston Blair, Jr. of Missouri	429,883	50.59%	33	100.00%
	Republican	Ulysses S. Grant of Illinois	Schuyler Colfax of Indiana	419,888	49.41%	0	0.00%
Total				849,771	100.00%	33	100.00%

Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
"1868 Presidential General Election Results - New York".

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