1852 United States presidential election in New York
The 1852 United States presidential election in New York took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose 35 representatives, or electors to the Electoral College, who voted for President and Vice President.
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| Turnout | 84.7%[1]  5.1 pp | |||||||||||||||||||||||||
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| Elections in New York State |
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New York voted for the Democratic candidate, Franklin Pierce, over the Whig Party candidate, Winfield Scott. Pierce won the state by a margin of 5.21%.
Results
| 1852 United States presidential election in New York[2] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Franklin Pierce of New Hampshire | William Rufus DeVane King of Alabama | 262,083 | 50.18% | 35 | 100.00% | ||
| Whig | Winfield Scott of New Jersey | William Alexander Graham of North Carolina | 234,882 | 44.97% | 0 | 0.00% | ||
| Free Soil | John Parker Hale of New Hampshire | George Washington Julian of Indiana | 25,329 | 4.85% | 0 | 0.00% | ||
| Total | 522,294 | 100.00% | 35 | 100.00% | ||||
References
- Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
- "1852 Presidential General Election Results - New York". U.S. Election Atlas. Retrieved 24 December 2013.
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