1908 United States presidential election in Indiana
The 1908 United States presidential election in Indiana took place on November 3, 1908. Voters chose 15 representatives, or electors to the Electoral College, who voted for president and vice president.
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Elections in Indiana |
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Indiana voted for the Republican nominee, Secretary of War William Howard Taft, over the Democratic nominee, former U.S. Representative William Jennings Bryan. Taft won the state by a narrow margin of 1.49%.
Results
1908 United States presidential election in Indiana[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | William Howard Taft of Ohio | James Schoolcraft Sherman of New York | 348,993 | 48.40% | 15 | 100.00% | ||
Democratic | William Jennings Bryan of Nebraska | John Worth Kern of Indiana | 338,262 | 46.91% | 0 | 0.00% | ||
Prohibition | Eugene Wilder Chafin of Illinois | Aaron Sherman Watkins of Ohio | 18,845 | 2.50% | 0 | 0.00% | ||
Socialist | Eugene Victor Debs of Indiana | Benjamin Hanford of New York | 13,476 | 1.87% | 0 | 0.00% | ||
People's | Thomas Edward Watson of Georgia | Samuel Williams of Indiana | 1,193 | 0.17% | 0 | 0.00% | ||
Socialist Labor | August Gillhaus of New York | Donald L. Munro of Virginia | 643 | 0.09% | 0 | 0.00% | ||
Independence | Thomas Louis Hisgen of Massachusetts | John Temple Graves of Georgia | 514 | 0.07% | 0 | 0.00% | ||
Total | 721,126 | 100.00% | 15 | 100.00% |
References
- "1908 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved 23 December 2013.
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