1908 United States presidential election in Rhode Island
The 1908 United States presidential election in Rhode Island took place on November 3, 1908 as part of the 1908 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.
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County Results
Taft 50-60% 60-70%
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Elections in Rhode Island |
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Rhode Island voted for the Republican nominee, Secretary of War William Howard Taft, over the Democratic nominee, former U.S. Representative William Jennings Bryan. Taft won the state by a margin of 26.6%.
With 60.76% of the popular vote, Rhode Island would be Taft's fifth strongest victory in terms of percentage in the popular vote after Vermont, Maine, Michigan and North Dakota.[1]
Results
1908 United States presidential election in Rhode Island[2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | William Howard Taft of Ohio | James Schoolcraft Sherman of New York | 43,942 | 60.76% | 4 | 100.00% | ||
Democratic | William Jennings Bryan of Nebraska | John Worth Kern of Indiana | 24,706 | 34.16% | 0 | 0.00% | ||
Socialist | Eugene Victor Debs of Indiana | Benjamin Hanford of New York | 1,365 | 1.89% | 0 | 0.00% | ||
Independence | Thomas Louis Hisgen of Massachusetts | John Temple Graves of Georgia | 1,105 | 1.53% | 0 | 0.00% | ||
Prohibition | Eugene Wilder Chafin of Illinois | Aaron Sherman Watkins of Ohio | 1,016 | 1.40% | 0 | 0.00% | ||
Socialist Labor | August Gillhaus of New York | Donald L. Munro of Virginia | 183 | 0.25% | 0 | 0.00% | ||
Total | 72,317 | 100.00% | 4 | 100.00% |
References
- "1908 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
- "1908 Presidential General Election Results - Rhode Island". U.S. Election Atlas. Retrieved 23 December 2013.
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