1988 United States Senate election in Ohio

The 1988 United States Senate election in Ohio was held on November 8, 1988. Incumbent Democratic U.S. Senator Howard Metzenbaum won re-election.[1] As of 2020, this is the last time in a presidential election year Ohio voted differently for president and for senate.

1988 United States Senate election in Ohio

November 8, 1988
 
Nominee Howard Metzenbaum George Voinovich
Party Democratic Republican
Popular vote 2,480,038 1,872,716
Percentage 57.0% 42.3%

County Results
Metzenbaum:      50–60%      60–70%      70–80%
Voinovich:      50-60%      60-70%

U.S. senator before election

Howard Metzenbaum
Democratic

Elected U.S. Senator

Howard Metzenbaum
Democratic

Major candidates

Democratic

Republican

Results

1988 United States Senate election in Ohio
Party Candidate Votes %
Democratic Howard Metzenbaum (incumbent) 2,480,038 56.97%
Republican George Voinovich 1,872,716 42.31%
Independent David Marshall 151 0.00%
Majority 607,322 8.68%
Turnout 4,352,905 100.00%
Democratic hold

See also

References

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