1988 United States Senate election in Wyoming
The 1988 United States Senate election in Wyoming took place on November 8, 1988. Incumbent Republican U.S. Senator Malcolm Wallop ran for re-election to a third term, and was narrowly re-elected, defeating the Democratic candidate John Vinich by a margin of a little over 1,300 votes.[1]
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 County Results Wallop: 50-60% 60-70% 70-80% Vinich: 50–60% 60–70% | |||||||||||||||||
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| Elections in Wyoming |
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Major candidates
Democratic
- John P. Vinich, Wyoming State Senator
Republican
- Malcolm Wallop, incumbent U.S. Senator
General election
Despite being a reliably Republican state, Vinich, a Democrat, was able to impressively compete with Wallop. During the campaign, Wallop attacked Vinich as being a tax-and-spend liberal who was beholden to labor and anti-business.[1] Vinich, in turn, cited his "A" score he got from the National Rifle Association due to his votes in the Wyoming Legislature to counter Wallop's attacks, and possibly attract conservative voters.[1]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Malcolm Wallop (Incumbent) | 91,143 | 50.37% | |
| Democratic | John P. Vinich | 89,821 | 49.64% | |
| Republican hold | ||||
See also
References
- "THE 1988 ELECTIONS: West; WYOMING". The New York Times. November 9, 1988. Retrieved May 16, 2015.
- "Our Campaigns - WY US Senate Race - Nov 08, 1988". ourcampaigns.com. Retrieved May 10, 2015.