1828 United States presidential election in Georgia

In the 1828 United States presidential election, Georgia voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Georgia by a margin of 93.58%.

1828 United States presidential election in Georgia

October 31 – December 2, 1828
 
Nominee Andrew Jackson John Quincy Adams
Party Democratic National Republican
Home state Tennessee Massachusetts
Running mate John C. Calhoun Richard Rush
Electoral vote 9 0
Popular vote 19,362 642
Percentage 96.79% 3.21%

Seven Georgian electors voted for William Smith for vice president, rather than Jackson's official running mate, John C. Calhoun.[1]

Results

United States presidential election in Georgia, 1828[2]
Party Candidate Votes Percentage Electoral votes
Democratic Andrew Jackson 19,362 96.79% 9
National Republican John Quincy Adams 642 3.21% 0
Totals 20,004 100.0% 9

References

  1. "Electoral Votes for President and Vice President, 1821-1837 – 1828 Election for the Eleventh Term". National Archives and Records Administration. Retrieved 6 September 2018.
  2. "1828 Presidential General Election Results - Georgia". U.S. Election Atlas. Retrieved 28 February 2013.


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