1836 United States presidential election in Georgia

The 1836 United States presidential election in Georgia took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for president and vice president.

United States presidential election in Georgia, 1836

November 3 – December 7, 1836


Nominee	Hugh White	Martin Van Buren
Party	Whig	Democratic
Home state	Tennessee	New York
Running mate	John Tyler	Richard Johnson
Electoral vote	11	0
Popular vote	24,481	22,778
Percentage	51.80%	48.20%

Federal government

Presidential elections
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Presidential primaries
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U.S. Senate elections
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State government

Gubernatorial elections
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Other elections
2006 2008 2010 2014 2016 2018 2020
Georgia State Senate elections
2010 2016 2018 2020
Georgia House of Representatives elections
2010 2016 2018 2020

Georgia voted for Whig candidate Hugh White over the Democratic candidate, Martin Van Buren. White won Georgia by a margin of 3.6%.

Results

United States presidential election in Georgia, 1836[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Whig	Hugh White	24,481	51.80%	11
	Democratic	Martin Van Buren	22,778	48.20%	0
Totals			47,259	100.0%	11

References

"1836 Presidential General Election Results - Georgia". U.S. Election Atlas. Retrieved 4 August 2012.

State and district results of the 1836 United States presidential election
Alabama Arkansas Connecticut Delaware Georgia Illinois Indiana Kentucky Louisiana Maine Maryland Massachusetts Michigan Mississippi Missouri New Hampshire New Jersey New York North Carolina Ohio Pennsylvania Rhode Island South Carolina Tennessee Vermont Virginia

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