1828 United States presidential election in New Jersey

The 1828 United States presidential election in New Jersey took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

1828 United States presidential election in New Jersey

October 31 – December 2, 1828
 
Nominee John Quincy Adams Andrew Jackson
Party National Republican Democratic
Home state Massachusetts Tennessee
Running mate Richard Rush John C. Calhoun
Electoral vote 8 0
Popular vote 23,753 21,809
Percentage 52.12% 47.86%

New Jersey voted for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won New Jersey by a narrow margin of 4.26%.

Results

1828 United States presidential election in New Jersey[1]
Party Candidate Votes Percentage Electoral votes
National Republican John Quincy Adams 23,753 52.12% 8
Democratic Andrew Jackson 21,809 47.86% 0
N/A Other 8 0.02% 0
Totals 45,570 100.0% 8

See also

References

  1. "1828 Presidential General Election Results - New Jersey". U.S. Election Atlas. Retrieved 28 February 2013.


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