1856 United States presidential election in New Jersey
The 1856 United States presidential election in New Jersey took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.
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Elections in New Jersey |
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New Jersey voted for the Democratic candidate, James Buchanan, over Republican candidate, John C. Frémont, and the Know Nothing candidate, Millard Fillmore. Buchanan won the state by a margin of 13.43 percentage points, and would be the last Democratic presidential candidate to carry Cumberland County until Franklin D. Roosevelt in 1936, and the last to carry Passaic County until Roosevelt in 1932.[1]
Results
1856 United States presidential election in New Jersey[2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | James Buchanan of Pennsylvania | John C. Breckinridge of Kentucky | 46,943 | 47.23% | 7 | 100.00% | ||
Republican | John C. Frémont of California | William L. Dayton of New Jersey | 28,338 | 28.51% | 0 | 0.00% | ||
Know Nothing | Millard Fillmore of New York | Andrew Jackson Donelson of Tennessee | 24,115 | 24.26% | 0 | 0.00% | ||
Total | 99,396 | 100.00% | 7 | 100.00% |
References
- Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 258-259 ISBN 0786422173
- "1856 Presidential General Election Results – New Jersey".
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