1836 United States presidential election in Pennsylvania
The 1836 United States presidential election in Pennsylvania took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 30 representatives, or electors to the Electoral College, who voted for President and Vice President.
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Elections in Pennsylvania |
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Pennsylvania voted for the Democratic candidate, Martin Van Buren, over the Whig candidate, William Henry Harrison. Van Buren won Pennsylvania by a narrow margin of 2.36%.
Results
1836 United States presidential election in Pennsylvania[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Martin Van Buren | 91,457 | 51.18% | 30 | |
Whig | William Henry Harrison | 87,235 | 48.82% | 0 | |
Totals | 178,692 | 100.0% | 30 | ||
References
- "1836 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved 4 August 2012.
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