1836 United States presidential election in Massachusetts
The 1836 United States presidential election in Massachusetts took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 14 representatives, or electors to the Electoral College, who voted for President and Vice President.
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Turnout | 43.4%[1] 4.0 pp | |||||||||||||||||||||||||
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Elections in Massachusetts |
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Massachusetts voted for Whig candidate and state native Daniel Webster over the Democratic candidate, Martin Van Buren. Webster won Massachusetts by a margin of 10.32%.
Results
1836 United States presidential election in Massachusetts[2] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Whig | Daniel Webster | 41,201 | 55.13% | 14 | |
Democratic | Martin Van Buren | 33,486 | 44.81% | 0 | |
N/A | Other | 45 | 0.06% | 0 | |
Totals | 74,732 | 100.0% | 14 | ||
References
- Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
- "1836 Presidential General Election Results - Massachusetts". U.S. Election Atlas. Retrieved 4 August 2012.
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