1856 United States presidential election in Delaware

The 1856 United States presidential election in Delaware took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

1856 United States presidential election in Delaware

November 4, 1856
 
Nominee James Buchanan Millard Fillmore
Party Democratic Know Nothing
Home state Pennsylvania New York
Running mate John C. Breckinridge Andrew Jackson Donelson
Electoral vote 3 0
Popular vote 8,004 6,275
Percentage 54.83% 42.99%

President before election

Franklin Pierce
Democratic

Elected President

James Buchanan
Democratic

Delaware voted for the Democratic candidate, James Buchanan, over the Republican candidate, John C. Frémont, and the Know Nothing candidate, Millard Fillmore.

Buchanan won the state by a margin of 11.84%.

Results

1856 United States presidential election in Delaware[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic James Buchanan of Pennsylvania John C. Breckinridge of Kentucky 8,004 54.83% 3 100.00%
Know Nothing Millard Fillmore of New York Andrew Jackson Donelson of Tennessee 6,275 42.99% 0 0.00%
Republican John C. Frémont of California William L. Dayton of New Jersey 310 2.12% 0 0.00%
N/A Others Others 9 0.06% 0 0.00%
Total 14,598 100.00% 3 100.00%

See also

References


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