1861 Belgian general election
Partial general elections were held in Belgium on 11 June 1861.[1][2] In the elections for the Chamber of Representatives the result was a victory for the Liberal Party, which won 66 of the 116 seats.[2] Voter turnout was 58.4%, although only 47,555 people were eligible to vote.
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58 of the 116 seats in the Chamber of Representatives 57 seats needed for a majority | |||||||||||||||||||||||||||||||
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This article is part of a series on the politics and government of Belgium |
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Under the alternating system, elections for the Chamber of Representatives were only held in four out of the nine provinces: Hainaut, Limburg, Liège and East Flanders.
Results
Chamber of Representatives
Party | Votes | % | Seats | ||
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Won | Total | +/– | |||
Liberal Party | 15,979 | 57.5 | 36 | 66 | –3 |
Catholics | 11,799 | 42.5 | 22 | 50 | +3 |
Invalid/blank votes | 2,760 | – | – | – | – |
Total | 30,538 | 100 | 58 | 116 | 0 |
Registered voters/turnout | 47,555 | 58.4 | – | – | – |
Source: Mackie & Rose,[3] Sternberger et al. |
References
- Codebook Constituency-level Elections Archive, 2003
- Sternberger, D, Vogel, B & Nohlen, D (1969) Die Wahl der Parlamente: Band I: Europa - Erster Halbband, p105
- Thomas T Mackie & Richard Rose (1991) The International Almanac of Electoral History, Macmillan, p46
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