1896 Belgian general election
Partial legislative elections were held in Belgium on 5 and 12 July 1896.[1] Under the alternating system, elections were held in only five out of the nine provinces: Antwerp, Brabant, Luxembourg, Namur and West Flanders. Thus, only 77 seats out of the 152 seats in the Chamber of Representatives were up for election. The Catholic Party retained their absolute majority.[2]
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This article is part of a series on the politics and government of Belgium |
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The Liberal Party, who lost two-thirds of their seats in the previous elections, saw their number of seats decrease further.
Results
Party | Votes | % | Seats won | Total seats | +/– |
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Catholic Party | 492,541 | 49.68 | 72 | 108 | +6 |
Liberal Party | 193,563 | 19.52 | 1 | 11 | –6 |
Belgian Labour Party | 150,260 | 15.16 | 0 | 27 | 0 |
Liberal-Socialist Kartels | 49,614 | 5.00 | 4 | 4 | 0 |
Other parties | 105,394 | 10.63 | 0 | 1 | 0 |
Invalid/blank votes | - | – | – | – | - |
Total | 991,372 | 100 | 77 | 152 | 0 |
Source: Belgian Elections |
References
- Nohlen, Dieter; Stöver, Philip (31 May 2010). Elections in Europe: A data handbook. Nomos Verlagsgesellschaft. p. 289. ISBN 978-3-8329-5609-7.
- Nohlen & Stöver, p307
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