1884 United States presidential election in West Virginia

The 1884 United States presidential election in West Virginia took place on November 4, 1884, as part of the 1884 United States presidential election. West Virginia voters chose six representatives, or electors, to the Electoral College, who voted for president and vice president.[2]

1884 United States presidential election in West Virginia

November 4, 1884
Turnout21.37% of the total population 3.16 pp[1]
 
Nominee Grover Cleveland James G. Blaine
Party Democratic Republican
Home state New York Maine
Running mate Thomas A. Hendricks John A. Logan
Electoral vote 6 0
Popular vote 67,311 63,096
Percentage 50.94% 47.75%

County Results

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

West Virginia was won by Grover Cleveland, the 28th governor of New York, (DNew York), running with the former governor of Indiana Thomas A. Hendricks, with 50.94% of the popular vote, against Secretary of State James G. Blaine (R-Maine), running with Senator John A. Logan, with 47.75% of the vote.[2]

The Prohibition Party chose John St. John, the former governor of Kansas, and former Maryland State Senator William Daniel as their presidential and vice-presidential candidates and received 0.71% of the vote. The Greenback and Anti-Monopoly Parties both chose major general and former governor of Massachusetts Benjamin Butler and Absolom M. West, an unseated Mississippi representative, received 0.60% of the vote.

Results

1884 United States presidential election in West Virginia[2]
Party Candidate Votes %
Democratic Grover Cleveland 67,311 50.94%
Republican James G. Blaine 63,096 47.75%
Prohibition John St. John 939 0.71%
Greenback Benjamin Butler 799 0.60%
Total votes 132,145 100.00%

References


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