1928 United States presidential election in West Virginia

1928 United States presidential election in West Virginia
	November 6, 1928
	November 6, 1928
Hoover 50-60% 60-70% 70-80% 80-90%	Smith 50-60%
President before election; Calvin Coolidge; Republican	Elected President ; Herbert Hoover; Republican

The 1928 United States presidential election in West Virginia took place on November 6, 1928, as part of the 1928 United States Presidential Election which was held throughout all contemporary 48 states. Voters chose eight representatives, or electors to the Electoral College, who voted for president and vice president.

West Virginia voted for the Republican nominee, Secretary of Commerce Herbert Hoover of California, over the Democratic nominee, Governor Alfred E. Smith of New York. Hoover's running mate was Senate Majority Leader Charles Curtis of Kansas, while Smith ran with Senator Joseph Taylor Robinson of Arkansas.

Hoover won the state by a margin of 17.39%. This was the last time that a non-incumbent Republican won West Virginia until 2000.

Results

1928 United States presidential election in West Virginia[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	Herbert Hoover	375,551	58.43%	8
	Democratic	Alfred E. Smith	263,784	41.04%	0
	Prohibition	William F. Varney	1,703	0.26%	0
	Socialist	Norman Thomas	1,313	0.20%	0
	Workers	William Z. Foster	401	0.06%	0
	N/A	Write-ins	9	0.01%	0
Totals			642,752	100.00%	8

References

"1928 Presidential General Election Results - West Virginia". Dave Leip's Atlas of U.S. Presidential Elections. Retrieved 2013-08-02.

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[1] "1928 Presidential General Election Results - West Virginia". Dave Leip's Atlas of U.S. Presidential Elections. Retrieved 2013-08-02.