1948 United States presidential election in West Virginia
The 1948 United States presidential election in West Virginia took place on November 2, 1948, as part of the 1948 United States presidential election. West Virginia voters chose eight[2] representatives, or electors, to the Electoral College, who voted for president and vice president.
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All 8 West Virginia votes to the Electoral College | ||||||||||||||||||||||||||
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 County Results
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| Elections in West Virginia |
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West Virginia was won by incumbent President Harry S. Truman (D–Missouri), running with Senator Alben W. Barkley, with 57.32% of the popular vote, against Governor Thomas Dewey (R–New York), running with Governor Earl Warren, with 42.24% of the popular vote.[3][4]
Results
| Party | Candidate | Votes | % | |
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| Democratic | Harry S. Truman (inc.) | 429,188 | 57.32% | |
| Republican | Thomas Dewey | 316,251 | 42.24% | |
| Progressive | Henry A. Wallace | 3,311 | 0.44% | |
| Total votes | 748,750 | 100.00% | ||
References
- "United States Presidential election of 1948 – Encyclopædia Britannica". Retrieved December 19, 2017.
- "1948 Election for the Forty-First Term (1949–53)". Retrieved December 19, 2017.
- "1948 Presidential General Election Results – West Virginia". Retrieved December 19, 2017.
- "The American Presidency Project – Election of 1948". Retrieved December 19, 2017.
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