1896 Hungarian parliamentary election
Parliamentary elections were held in Hungary between 29 October and 4 November 1896 . The result was a victory for the Liberal Party, which won 290 of the 413 seats.
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All 413 seats in the Diet 207 seats needed for a majority | ||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
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This article is part of a series on the politics and government of Hungary |
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Results
Party | Seats | % | Parliamentary role |
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Liberal Party | 290 | 70,21% | government |
Party of Independence and '48 | 50 | 12,10% | opposition |
National Party | 33 | 8,23% | opposition |
Catholic People's Party | 18 | 4,36% | opposition |
'Ugron' Party of Independence and '48 | 11 | 2,66% | opposition |
Independent | 10 | 2,42% | independent |
Romanian National Party | 1 | 0,24% | opposition |
Total | 413 | 100% | — |
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