1852 United States presidential election in Michigan

The 1852 United States presidential election in Michigan took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for President and Vice President.

1852 United States presidential election in Michigan

November 2, 1852
 
Nominee Franklin Pierce Winfield Scott John P. Hale
Party Democratic Whig Free Soil
Home state New Hampshire New Jersey New Hampshire
Running mate William R. King William A. Graham George W. Julian
Electoral vote 6 0 0
Popular vote 41,842 33,860 7,237
Percentage 50.45% 40.83% 8.73%

County Results

President before election

Millard Fillmore
Whig

Elected President

Franklin Pierce
Democratic

Michigan voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott and Free Soil candidate John P. Hale. Pierce won Michigan by a margin of 9.62%.

As of the 2020 presidential election, this is the last and only time Sanilac County voted for a Democratic Presidential candidate.[1] It would be the last time Michigan would send a full slate of Democratic electors to the Electoral College until Franklin Delano Roosevelt in 1932, although it did send five Grover Cleveland electors in 1892.[2]

Results

1852 United States presidential election in Michigan[3][4]
Party Candidate Votes %
Democratic Franklin Pierce 41,842 50.45%
Whig Winfield Scott 33,860 40.83%
Free Soil John P. Hale 7,237 8.73%
Total votes 82,939 100%

References

  1. Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 222-227 ISBN 0786422173
  2. Menendez; The Geography of Presidential Elections in the United States, p. 62
  3. "1852 Presidential General Election Results -Michigan". U.S. Election Atlas. Retrieved 2 December 2017.
  4. "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 2 December 2017.


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